Angular中$state.go页面跳转并传递参数的方法

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遇到一个页面跳转的时候,在跳转后的页面获取跳转前页面的数据,我想到用一种是localstorage,一种用broadcast和on,然后老大说不用这么麻烦,既然都$state.go了直接带参数,这次就介绍一下$state.go页面跳转传递参数。

1.路由页面(注意这里要在路由上添加一个参数用于传递数据,不然在页面跳转的时候会filter)

 .state("home.workpiece",{ // 跳转前的页面
   url:"/workpiece",
   views: {
    home: {
     templateUrl: prefix + "project/workpiece.html",
     controller: "workpieceCtrl"
    }
   }
  })
  .state("home.workpieceDetail",{  //跳转后的页面
   url:"/workpieceDetail?workpieceList",
   views: {
    home: {
     templateUrl: prefix + "project/workpiece_detail.html",
     controller: "workpieceDetailCtrl"
    }
   }
  })

    也可以将参数放在params中  

 .state("home.workpieceDetail",{
   url:"/workpieceDetail",
   views: {
    home: {
     templateUrl: prefix + "project/workpiece_detail.html",
     controller: "workpieceDetailCtrl"
    }
   },
   params: {workpieceList:null}
  })

2.在workpieceCtrl中 

3.workpieceDetailCtrl中

这样就可以将在页面跳转的时候传递数据了。希望对大家有所帮助!